Saturday, September 27th, 2008
In the inverting amplifier,only one input is applied and that is to the inverting input terminal.The non-inverting input terminal is grounded since V1=0V and V2=Vin.
Therefore Vo = -A(Vin)
The negative sign indicates the output voltage is out of phase with respect to input by 180 degree or is of opposite polarity.Thus in the inverting amplifier,The input signal is amplified by gain A and is also inverted at the output.
Non-Inverting Amplifier
In this configuration ,the input is given to the non inverting input terminal and the inverting terminal is connected to ground.
In the circuit,V1=Vin and V2=0V therefore the output voltage Vo=AVin.This means that the output voltage is larger than the input voltage by gain A and is in phase with the input signal
read more
If you enjoyed this post, make sure you subscribe to my RSS feed! Read more »
Posted in Linear Integrated Circuits, op-amp, op-amp applications | No Comments »
Friday, September 26th, 2008
The figure shows the open loop configuration of differential amplifier in which the input signals Vin1 and Vin2 are applied to the positive and negative input terminals since the op-amp amplifies the difference between the two input signals,this configuration is called differential amplifier.Vin1 and Vin2 could be either ac or dc voltages.The source resistances Rin1 and Rin2 are negligible compared to the input resistance Ri.The voltage drop across the resistors can be assumed to be zero,which then implies that V1=Vin and V2=Vin2.The the output voltage Vo=A(Vin1-Vin2).
The output voltage is equal to the voltage gain A times the difference between the two input voltage.The polarity of the output voltage is dependent on the polarity of the input difference voltage(Vin1-Vin2).In open loop read more
If you enjoyed this post, make sure you subscribe to my RSS feed! Read more »
Posted in Linear Integrated Circuits, op-amp, op-amp applications | No Comments »